Talk-Polywell.org

You're wrong on the 159 kNm torque equating to energy here. In a rotational system, power (energy per second) equates to torque times the angular velocity of the flywheel. Which should hold for either end of the energy balance: Power output = 10MW = 10.000.000 J/s angular velocity: 600RPM = 10 RPS =...

It isn't me that's confused. [Stoney3K, all you've done is calculate the work done by the M-E thruster, not the input power requirement. It's no surprise that it matches my own calculation of the work done by the M-E thruster.] Consider two cases. 1) A Mach-effect thruster on a test stand, wired to...

Please keep your terminology in mind here. Kinetic energy is something that is already stored in a moving object (e.g. flywheel or spacecraft). Force times distance is work , which is the change of total kinetic energy in the system. This is consistent with Newton's Second Law of motion. After all, ...

How can antimatter have a repulsive force on other masses, when it has positive mass but opposing charge?

In theory, an antimatter atom should even be neutral so it should have no different interaction with the outside world as any regular hydrogen atom.

I do recall a stray LENR unit somewhere in Italy.

Although I'm not sure 10kW would cut it for the entire Texas state. Probably only for the Eastern half.

Can I run it off a 50 amp breaker, or do I have to revert back to my trusty old gas kettle?

You're blindly applying the inverse square law to determine the dose received by said worker. a) inverse square law is the one that applies, and is correctly applied blindly (why not? and if why not, do you have a better one to apply!?) I wasn't implying the law wouldn't apply. I was only trying to...

I don't think oil prices will change a lot when WB-8 hits first plasma and works as advertised. It becomes a different story when the first fusion reactor starts delivering juice to the grid. This means there will be a gradual decrease in demand for electricity from other sources (e.g. hydrocarbon b...

Assume we have a very small reactor producing 30 kW of total fusion power (a full-scale power reactor might produce 100,000 times more than this) and 30 W in the form of neutrons. If there is no significant shielding , a worker in the next room, 10 m away, might intercept (0.5 m²)/(4 pi (10 m)2) = ...

so then "all" one has left to do is explain quarks and their interactions. oh, and the weak field. I'd first like to see them take a crack at explaining gravity, and ways to influence it. The big G is, at this time, still a magical black box which just somehow seems to work. If we can find out *how...

so that would seem to explain, geometrically, how an electron-positron pair annihilate into a photon and vice-versa. That does make sense on some level, even with my just-beyond-basic understanding of quantum physics and calculus. The question is, what does that amount to when you take the 'heavier...

This might be preferred for making an SSTO vehicle or other such related systems. It would even be a perfect candidate for SSTO, since the reason it carries an enormous load of fuel is because it needs to produce a truckload of thrust to counteract air resistance along with gravity. Hey, wait, what...

If the 3He byproduct is actually ejected from the reactor as such, it could in itself serve as fusion fuel for spacecraft or capital ships. I'm not sure where 3He has been mentioned. Have I made a typo somewhere? The reaction is; p+ 15N -> 4He + 12C + 5MeV http://en.wikipedia.org/wiki/Aneutronic_fu...

Indeed, it is a component of air. There is enough 15N in the atmosphere, mind, to generate the same energy as around 100 million years of current power output. Wouldn't that mean that, once we get even *a* viable fusion reaction out of p-N15, the whole energy economics would collapse like a house o...

Food for thought here: If we could make p-15N work, we'd essentally solve the world's energy problem once and for all. You could simply drop one of these things in the middle of nowhere and bootstrap it with some energy storage, after which it would literally run on thin air. 0,37% of the air we bre...