The current producing the inductive heating will flow primarily on the outside surface of the stainless steel reaction vessel (RV) wall due to the skin effect.
No. Skin effect is an RF behaviour. Low frequency (mains) or DC will not produce skin effect.
Little or a reduced current will flow on the inside surface of the RV wall.
No. The wall, as a conductor, will distribute the current flux equally (assuming DC or low freq mains, as above). But the current doesn't look like it is being passed through the reactor walls itself, so the point is 'not even wrong'.
No magnetic field will exist on the inside of the RV where the hydrogen is pressurized.
There will always be some mag field, if a current is flowing nearby without a magnetic material between them.
The magnetic field lines will be parallel to the circumference of the RV cylinder causing the heating current to flow along the skin of the RV.This is prescribed by the right hand rule.
The heating current flows due to Gauss' law - suck electrons out of one end of a conductor, and they will flow into the other end, if you put electrons there. It's called a 'circuit'. No 'heating current' passes through the chamber walls, though. There would be a low resistance coil that takes the current, and heats up.
There will be a large negative electrostatic field produced by the flowing electrons which form the inductive heating current.
No, it'll be very low, because the inductive heater will be a low resistance path. There will be no field at all from the heating element within the chamber itself, because it would act as a Faraday cage.
This negative current charge will attract the positive hydrogen ions into the oxygen vacancies on the nickel oxide powder lying on the inside surface of the RV wall.
This attractive force will supplement the force exerted by the electronegative oxygen atoms within the NiO at or very near the inner surface of the RV wall.
At startup, the induced current will be substantial at about 10 amps.
The rest sounds like random words.