This Wikipedia article states:
At first glimpse this would mean a 1GW reactor to produce 2MW of neutrons - quite much.Detailed calculations show that at least 0.1% of the reactions in a thermal p–11B plasma would produce neutrons, and the energy of these neutrons would account for less than 0.2% of the total energy released.
But this calculation was made for a thermal plasma. For a nonthermal monoenergetic ion distribution like in a polywell the neutron production should be several orders of magnitudine lower. Since there are nearly no ions with the optimal energy for these side reactions.
Wikipedia states two side reactions that involve the reactants and products of the primary fusion reaction.
First:
Well, in a polywell the alphas do leave the plasma as soon as they are created! Making the plasma hot by thermalising them would be unwanted!These neutrons come primarily from the reaction
11B + α → 14N + n + 157 keV
... A clever magnetic confinement scheme could in principle suppress the first reaction by extracting the alphas as soon as they are created, but then their energy would not be available to keep the plasma hot.
And even if some alphas collide with B11s their energy will be much to high to have a significant cross section for fusion. Only by thermalising they would go through the right energy for the reaction.
So this reaction will not happen for lack of alphas with energy low enough.
Second:
In a polywell the ion distribution is monoenergetic, so there is no high energy tail of the ion distribution. So this reaction will not happen either. This time for lack of ions with enough energy to do it.Another significant source of neutrons is the reaction
11B + p → 11C + n - 2.8 MeV
... The second reaction could in principle be suppressed relative to the desired fusion by removing the high energy tail of the ion distribution, but this would probably be prohibited by the power required to prevent the distribution from thermalizing.
Another neutron source claimed are deuterons from isotopical unclean hydrogen.
But at first natural hydrogen has a very low deuterium content to begin with and again the energy distribution in a polywell optimised for p-B11 will be wrong for these reactions.Finally, isotopically pure fuel will have to be used and the influx of impurities into the plasma will have to be controlled to prevent neutron-producing side reactions like these:
11B + d → 12C + n + 13.7 MeV
d + d → 3He + n + 3.27 MeV
So p-B11 per se might not be called truly aneutronic. But p-B11 in a polywell would come much nearer to this ideal.
Much more then by neutrons I would be concerned by gammas from this reaction:
But here even the wall of the vacuum chamber should absorb a significant part of these gammas.In addition to neutrons, large quantities of hard X-rays will be produced by bremsstrahlung, and 4, 12, and 16 MeV gamma rays will be produced by the fusion reaction
11B + p → 12C + γ + 16.0 MeV
with a branching probability relative to the primary fusion reaction of about 10−4.