Postby D Tibbets » Tue Jul 21, 2015 11:24 pm
Perhaps, and I repeat perhaps, you are overthinking it. would have an average with At low Beta the 'star points' occupy some volume, but if the cutoff is the depth where almost all electrons are on an escape path, the the dept from an average radius is modest. At high beta where the average radius is pushed out this is even less significant. The average radius of a roughly spherical volume will give the approximate answer. To refine this to a more accurate number you need to know various parameters like the B field strength, and associated density and energy. Also, the separation of the magnets need to be incorperated, the minor radius of the magnets, etc.
Estimated with a square volume- a simplification to avoid using pi. A cube of 5 liters would be about 17 cm on a side. A quasi sphere would have an average radius a little more than this.
Solving for a sphere of 5 liters volume:
4/3 pi r^3 = 5000cm^3
4.19 r^3= 5000 cm^3
r = cube root of (5000 cm^3/ 4.19)
r (average)= ~10.3 cm
Dan Tibbets
To error is human... and I'm very human.