Just to clarify hopefully (at least for myself), my estimate of the Magrid heat exposure follows. I'll use a square form facter for simplicity. A cube 3 meters on a side, has 3m^2 per side * 6 sides= 54 m total area. With 100 MW each m^2 would receive 2MW of heat. The actual Magrid surface exposure is only a fraction of this, but the ratio should hold (I think).charliem wrote:1.4 meters from a 100 MW machine center, each sq meter will receive about four times that figure (100MW/(4*pi*(1.4m)^2)MSimon wrote:The real world consideration is 1 MW/sq m and about 100 deg K delta T. Inlet of the cooling loop to outlet.
Still doable?
But only the inside facing half of theMagrid is directly exposed to the heat, while the outer side is not. Would this effectively half the heat/ m^2 number? And, if a significant portion of the 'heat' is penitrating neutrons, with a significant portion of them passing entirely through the Magrids, will this reduce the heat/ energy that needs to be absorbed (assuming the superconductor could survive a significant neutron flux)?
Once pass the magrid, the volume of the vacuum vessel will be significantly larger, so heat load should be considerably less.
Dan Tibbets