tomclarke wrote: Johan,
I must have been unclear because you have completely misunderstood my point.
Hi Tom,
On the contrary, you have not been unclear at all since what you claim is what I have also taught my students for more than 40 years before I realised that it must be wrong. And in fact by using the Lorentz transformation correctly it can be proved to be wrong. To start off: Let me give you a simple thought experiment: Consider a rod with length L moving past at a speed v which has a clock that can trigger a laser pulse at the rear end and a mirror at the front. Assume that when the rear end passes you, you synchronise your clock with the clock on the rod which then triggers a laser pulse to move along the rod to the mirror and to move back. How long will it take on your clock for the laser pulse to reach the mirror and how long to return to the laser?
I'll try again.
(1) you can only compare clocks when they are at the same space-time position.
Not true. Two identical perfect clocks which are stationary within an inertial reference frame do, no matter how far apart they are, keep time at exactly the same rate. They can also easily be synchronized to show exactly the same time. They are not at the same space-time position at all but keeping exactly the same time.
Therefore to evaluate time dilation you need to have two clocks which colocate at two different times on their event lines. This is not possible without one at least of the two clocks changing FOR.
They do colocate when they are synchronized when passing each other. And it is easy to determine the time elapsed by each clock within its own inertial reference frame and then to compare this. In fact I have done this in a previous post when I derived the times elapsed on each clock
within its own inertial reference frame when two identical spaceships, of equal length pass each other. And the result is that the elapsed time is exactly the same on both clocks.
(2) I claim that if one clock stays in its FOR and the other accerates away, then back (thereby changing FOR), the changing FOR clock will read slower when they are compared. this is not a paradox, since if the acceleration were symmetrical there would be no difference.
And as I have just posted above, I strongly suspect that the time rate of a clock within its own reference frame will not change owing to acceleration of the clock. I also proposed a simple experiment which can be used to test this hypothesis.
(3) This experiment, or something equivalent, is easily tested. I bet it has been.
Where and when: Please do not quote the clocks being flown around the world. The clocks must move or accelerate without any change in the gravitational field they experience.
The effect of changing FOR can easily be disambiguated from any gravitational effects.
Correct! Why has this not yet been done?
I am enjoying our conversation: It has now become clear that we need an experiment to determine who is correct or not correct. And as you have pointed out such an experiment should not be difficult to do. I predict that any motion of a clock including acceleration, outside a gravitational field will not affect the clock rate within the reference frame within which the clock remains stationary. Thus if the two twins experienced thye same gravitational field while travelling apart their clocks will show exactly the same time when they meet up again: No matter which one accelerated or whether the acceleration was symmetrical or not.