Just to clarify hopefully (at least for myself), my estimate of the Magrid heat exposure follows. I'll use a square form facter for simplicity. A cube 3 meters on a side, has 3m^2 per side * 6 sides= 54 m total area. With 100 MW each m^2 would receive 2MW of heat. The actual Magrid surface exposure is only a fraction of this, but the ratio should hold (I think).charliem wrote:1.4 meters from a 100 MW machine center, each sq meter will receive about four times that figure (100MW/(4*pi*(1.4m)^2)MSimon wrote:The real world consideration is 1 MW/sq m and about 100 deg K delta T. Inlet of the cooling loop to outlet.![]()
Still doable?
But only the inside facing half of theMagrid is directly exposed to the heat, while the outer side is not. Would this effectively half the heat/ m^2 number? And, if a significant portion of the 'heat' is penitrating neutrons, with a significant portion of them passing entirely through the Magrids, will this reduce the heat/ energy that needs to be absorbed (assuming the superconductor could survive a significant neutron flux)?
Once pass the magrid, the volume of the vacuum vessel will be significantly larger, so heat load should be considerably less.
Dan Tibbets